Discussion:
Element 115 created in Black Holes
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Oscar Vogel
2015-01-09 12:11:08 UTC
Permalink
A sufficient minimal amount of Element 115, Ununpentium, would correspond
and balance out a Black Holes. Its radius and the other characteristics
gets identical (volume, weight etc).

Why, because these heavy elements cannot collapse even more, since their
crystal structure already is packed ad absurdum up to maximum.

Hence, not even the light may escape from a sufficient amount of
Ununpentium. However to cancel the weak gravity exerted by Earth on a
small spaceship, will not provoke any problems. I have to evaluate it
numerically to see how much of Ununpentium is needed. According to
Relativity this should be possible.

Now using 2 or more identical amounts of Ununpentium will construct a
wormhole, so I can travel even faster through time and space. An estimate
would be that I need 2 x 0.05 m³ to do that.
Oscar Vogel
2015-01-09 12:39:33 UTC
Permalink
Post by Oscar Vogel
A sufficient minimal amount of Element 115, Ununpentium, would
correspond and balance out a Black Holes. Its radius and the other
characteristics gets identical (volume, weight etc).
Why, because these heavy elements cannot collapse even more, since their
crystal structure already is packed ad absurdum up to maximum.
Hence, not even the light may escape from a sufficient amount of
Ununpentium. However to cancel the weak gravity exerted by Earth on a
small spaceship, will not provoke any problems. I have to evaluate it
numerically to see how much of Ununpentium is needed. According to
Relativity this should be possible.
Now using 2 or more identical amounts of Ununpentium will construct a
wormhole, so I can travel even faster through time and space. An
estimate would be that I need 2 x 0.05 m³ to do that.
The Sun, stars and supernovas are not capable to produce this element.
What is left are Black Holes. Unfortunately you can't just travel the long
distance to the center of the galaxy.

Here come the particle accelerators into focus. They pretend being able to
generate micro Black Holes. Good enough to me, as far they can produce
them in sufficient quantities. In fact the confirmation on the existence
of Black Holes, micro Black Holes included, would concludes by a residual
production of all these heavy elements, here e115. This is what I need and
thank you for your help.
h***@yahoo.com
2015-01-09 15:44:31 UTC
Permalink
Post by Oscar Vogel
A sufficient minimal amount of Element 115, Ununpentium, would correspond
and balance out a Black Holes. Its radius and the other characteristics
gets identical (volume, weight etc).
Why, because these heavy elements cannot collapse even more, since their
crystal structure already is packed ad absurdum up to maximum.
Not true. Neutronium and quark matter are denser.
Post by Oscar Vogel
The Sun, stars and supernovas are not capable to produce this element.
It's possible that supernovae produce e115 since it can result from
high neutron fluxes, but the half-life of its most stable isotope is only
220 milliseconds.
Post by Oscar Vogel
Here come the particle accelerators into focus. They pretend being able
to generate micro Black Holes.
This was a concern by some before the LHC came online, but it has not
happened. Anyone who understands what very-high-energy cosmic rays do
in our atmosphere would understand that if it could happen, it would
already have happened.

Gary
Oscar Vogel
2015-01-09 23:17:06 UTC
Permalink
Post by h***@yahoo.com
Post by Oscar Vogel
Why, because these heavy elements cannot collapse even more, since
their crystal structure already is packed ad absurdum up to maximum.
Not true. Neutronium and quark matter are denser.
Then let's use that. Unobtainium should suit this application likewise.
Post by h***@yahoo.com
Post by Oscar Vogel
The Sun, stars and supernovas are not capable to produce this element.
It's possible that supernovae produce e115 since it can result from
high neutron fluxes, but the half-life of its most stable isotope is
only 220 milliseconds.
Untrue. e115 needs to be perfectly stable and not decay. In between e114
and 116 there is an island of stability in the structure. This would be
e115 and this is why.
Post by h***@yahoo.com
Post by Oscar Vogel
Here come the particle accelerators into focus. They pretend being able
to generate micro Black Holes.
This was a concern by some before the LHC came online, but it has not
happened. Anyone who understands what very-high-energy cosmic rays do
in our atmosphere would understand that if it could happen, it would
already have happened.
This is not the point, but the production of e115 as a residual product
out of that.
h***@yahoo.com
2015-01-10 00:26:18 UTC
Permalink
Post by Oscar Vogel
Post by h***@yahoo.com
Post by Oscar Vogel
Why, because these heavy elements cannot collapse even more, since
their crystal structure already is packed ad absurdum up to maximum.
Not true. Neutronium and quark matter are denser.
Then let's use that. Unobtainium should suit this application likewise.
Okay.
Post by Oscar Vogel
Post by h***@yahoo.com
Post by Oscar Vogel
The Sun, stars and supernovas are not capable to produce this element.
It's possible that supernovae produce e115 since it can result from
high neutron fluxes, but the half-life of its most stable isotope is
only 220 milliseconds.
Untrue. e115 needs to be perfectly stable and not decay. In between e114
and 116 there is an island of stability in the structure. This would be
e115 and this is why.
http://en.wikipedia.org/wiki/Ununpentium

"It is an extremely radioactive element; its most stable known isotope,
ununpentium-289, has a half-life of only 220 milliseconds."
Post by Oscar Vogel
Post by h***@yahoo.com
Post by Oscar Vogel
Here come the particle accelerators into focus. They pretend being able
to generate micro Black Holes.
This was a concern by some before the LHC came online, but it has not
happened. Anyone who understands what very-high-energy cosmic rays do
in our atmosphere would understand that if it could happen, it would
already have happened.
This is not the point, but the production of e115 as a residual product
out of that.
Still not dense enough. Even neutronium or quarkium aren't dense enough
unless compressed by many thousands of km of like material.

Gary
Oscar Vogel
2015-01-10 10:59:26 UTC
Permalink
Post by h***@yahoo.com
Post by Oscar Vogel
Untrue. e115 needs to be perfectly stable and not decay. In between
e114 and 116 there is an island of stability in the structure. This
would be e115 and this is why.
http://en.wikipedia.org/wiki/Ununpentium
"It is an extremely radioactive element; its most stable known isotope,
ununpentium-289, has a half-life of only 220 milliseconds."
This what is allowed to know, the mainstream. We need a second opinion
from a one in the field. But not even him may know what is going on behind
the scenes.

I understood it is about the constellation geometry/arrangement inside the
nucleus. A particular arrangement makes it stable long enough to be used
as such.
Post by h***@yahoo.com
Post by Oscar Vogel
This is not the point, but the production of e115 as a residual product
out of that.
Still not dense enough. Even neutronium or quarkium aren't dense enough
unless compressed by many thousands of km of like material.
Is not only about the density. You may be right, it needs also to decay
controllably. Controllably decay!

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