Discussion:
What is the 'volume' of a photon/wave packet?
(too old to reply)
RLH
2017-11-01 10:00:00 UTC
Permalink
It is well accepted that a photon/wave packet of EMR has dimensions and direction as it travels through space.

We know from long wavelengths that any wave packet/photon has lower energy and that short wavelengths wave packets/photons have higher energy.

How is that energy distributed in space during its travel? What volume of space at any 1 instance is time (a very short dT) does the photon/wave packet occupy?

What mechanism is it that small volume has greater energy than a larger volume?

What mechanism causes reflection, refraction, absorption, transmission, etc. of those photons/wave packets when they interact with matter? Give that the engagement time periods are very short as they 'pass through' any mass, plasma, gas, liquid, solid.
RLH
2017-11-01 10:34:48 UTC
Permalink
Post by RLH
It is well accepted that a photon/wave packet of EMR has dimensions and direction as it travels through space.
We know from long wavelengths that any wave packet/photon has lower energy and that short wavelengths wave packets/photons have higher energy.
How is that energy distributed in space during its travel? What volume of space at any 1 instance is time (a very short dT) does the photon/wave packet occupy?
What mechanism is it that small volume has greater energy than a larger volume?
What mechanism causes reflection, refraction, absorption, transmission, etc. of those photons/wave packets when they interact with matter? Give that the engagement time periods are very short as they 'pass through' any mass, plasma, gas, liquid, solid.
DSP and Fourier analysis are well known to be limited to the sample rate of the signal in both time (short dT) and space (short dP) but are used throughout the literature.

The 'box plot' (paricle, photon) devolving into a sinc function (wave function) seems a reasonable approach to these problems.
HGW, DSc.
2017-11-01 22:01:42 UTC
Permalink
Post by RLH
Post by RLH
It is well accepted that a photon/wave packet of EMR has dimensions and direction as it travels through space.
We know from long wavelengths that any wave packet/photon has lower energy and that short wavelengths wave packets/photons have higher energy.
How is that energy distributed in space during its travel? What volume of space at any 1 instance is time (a very short dT) does the photon/wave packet occupy?
What mechanism is it that small volume has greater energy than a larger volume?
What mechanism causes reflection, refraction, absorption, transmission, etc. of those photons/wave packets when they interact with matter? Give that the engagement time periods are very short as they 'pass through' any mass, plasma, gas, liquid, solid.
DSP and Fourier analysis are well known to be limited to the sample rate of the signal in both time (short dT) and space (short dP) but are used throughout the literature.
The 'box plot' (paricle, photon) devolving into a sinc function (wave function) seems a reasonable approach to these problems.
you will find various estimates for the time involved in the creation of
light quanta...even as long as 10-7 secs. They must also have a cross
section in order to have properties at all.

You might like to read my thesis on the Ballistic theory.
http://www.scisite.info/books/bath/bath.html

There are many answers there.
RLH
2017-11-01 22:46:02 UTC
Permalink
Post by HGW, DSc.
Post by RLH
Post by RLH
It is well accepted that a photon/wave packet of EMR has dimensions and direction as it travels through space.
We know from long wavelengths that any wave packet/photon has lower energy and that short wavelengths wave packets/photons have higher energy.
How is that energy distributed in space during its travel? What volume of space at any 1 instance is time (a very short dT) does the photon/wave packet occupy?
What mechanism is it that small volume has greater energy than a larger volume?
What mechanism causes reflection, refraction, absorption, transmission, etc. of those photons/wave packets when they interact with matter? Give that the engagement time periods are very short as they 'pass through' any mass, plasma, gas, liquid, solid.
DSP and Fourier analysis are well known to be limited to the sample rate of the signal in both time (short dT) and space (short dP) but are used throughout the literature.
The 'box plot' (paricle, photon) devolving into a sinc function (wave function) seems a reasonable approach to these problems.
you will find various estimates for the time involved in the creation of
light quanta...even as long as 10-7 secs. They must also have a cross
section in order to have properties at all.
You might like to read my thesis on the Ballistic theory.
http://www.scisite.info/books/bath/bath.html
There are many answers there.
Can you summarise/précis it for me?
Python
2017-11-02 01:47:09 UTC
Permalink
Post by RLH
Post by HGW, DSc.
Post by RLH
Post by RLH
It is well accepted that a photon/wave packet of EMR has dimensions and direction as it travels through space.
We know from long wavelengths that any wave packet/photon has lower energy and that short wavelengths wave packets/photons have higher energy.
How is that energy distributed in space during its travel? What volume of space at any 1 instance is time (a very short dT) does the photon/wave packet occupy?
What mechanism is it that small volume has greater energy than a larger volume?
What mechanism causes reflection, refraction, absorption, transmission, etc. of those photons/wave packets when they interact with matter? Give that the engagement time periods are very short as they 'pass through' any mass, plasma, gas, liquid, solid.
DSP and Fourier analysis are well known to be limited to the sample rate of the signal in both time (short dT) and space (short dP) but are used throughout the literature.
The 'box plot' (paricle, photon) devolving into a sinc function (wave function) seems a reasonable approach to these problems.
you will find various estimates for the time involved in the creation of
light quanta...even as long as 10-7 secs. They must also have a cross
section in order to have properties at all.
You might like to read my thesis on the Ballistic theory.
http://www.scisite.info/books/bath/bath.html
There are many answers there.
Can you summarise/précis it for me?
Oh dear... Still unable to make the difference between cranks (like HGW,
aka Henry Wilson, aka Ralph Rabbidge, Ken Seto, Pentcho Valev, etc. did
you have a look to "Immortal Fumbles" compilation?)
RLH
2017-11-02 08:42:58 UTC
Permalink
Post by Python
Post by RLH
Post by HGW, DSc.
Post by RLH
Post by RLH
It is well accepted that a photon/wave packet of EMR has dimensions and direction as it travels through space.
We know from long wavelengths that any wave packet/photon has lower energy and that short wavelengths wave packets/photons have higher energy.
How is that energy distributed in space during its travel? What volume of space at any 1 instance is time (a very short dT) does the photon/wave packet occupy?
What mechanism is it that small volume has greater energy than a larger volume?
What mechanism causes reflection, refraction, absorption, transmission, etc. of those photons/wave packets when they interact with matter? Give that the engagement time periods are very short as they 'pass through' any mass, plasma, gas, liquid, solid.
DSP and Fourier analysis are well known to be limited to the sample rate of the signal in both time (short dT) and space (short dP) but are used throughout the literature.
The 'box plot' (paricle, photon) devolving into a sinc function (wave function) seems a reasonable approach to these problems.
you will find various estimates for the time involved in the creation of
light quanta...even as long as 10-7 secs. They must also have a cross
section in order to have properties at all.
You might like to read my thesis on the Ballistic theory.
http://www.scisite.info/books/bath/bath.html
There are many answers there.
Can you summarise/précis it for me?
Oh dear... Still unable to make the difference between cranks (like HGW,
aka Henry Wilson, aka Ralph Rabbidge, Ken Seto, Pentcho Valev, etc. did
you have a look to "Immortal Fumbles" compilation?)
Can you summarise/précis your views so that I may compare the 2. Best effort wins the day.
HGW, DSc.
2017-11-02 16:10:30 UTC
Permalink
Post by RLH
Post by Python
Post by RLH
Post by HGW, DSc.
you will find various estimates for the time involved in the creation of
light quanta...even as long as 10-7 secs. They must also have a cross
section in order to have properties at all.
You might like to read my thesis on the Ballistic theory.
http://www.scisite.info/books/bath/bath.html
There are many answers there.
Can you summarise/précis it for me?
Oh dear... Still unable to make the difference between cranks (like HGW,
aka Henry Wilson, aka Ralph Rabbidge, Ken Seto, Pentcho Valev, etc. did
you have a look to "Immortal Fumbles" compilation?)
Can you summarise/précis your views so that I may compare the 2. Best effort wins the day.
He wont. He knows no science. 'Python' alias Dirk van de Moortel, is in
charge of the Einstein Conspiracy intelligence network. He keeps records
of all those who are a threat to the hundred year hoax and calls his
relativist ratpack into action whenever a newbie with a few brains
appears on the scene. By now, he knows who you are, where you live and
everything about your career. You are classed as a crackpot because you
ask sensible scientific questions. You will soon learn who the real
crackpots are.

Dirk thinks he knows who I am too...HAHAAHAHAHA!
p***@gmail.com
2017-11-02 03:33:28 UTC
Permalink
Photons do not have the property of size (volume). Nor do they have a trajectory.
RLH
2017-11-02 08:44:36 UTC
Permalink
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
The have a trajectory in the sense that are created and they die and travel some path between those 2 points.
Gary Harnagel
2017-11-02 11:17:36 UTC
Permalink
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
But the sun interacts with all the planets in the solar system, so that
means the sun is as big as the whole solar system according to your
assertion.
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?

BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Libor 'Poutnik' Stříž
2017-11-02 11:24:06 UTC
Permalink
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-02 12:39:34 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
See above.
Libor 'Poutnik' Stříž
2017-11-02 12:48:06 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
See above.
You did not say anything about the book.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-02 12:55:48 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
See above.
You did not say anything about the book.
I did observe about atoms on the light path meaning that all paths cannot be taken. They must be on a least squares straight line from A to B in sapce.
RLH
2017-11-02 13:06:22 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
See above.
You did not say anything about the book.
I did observe about atoms on the light path meaning that all paths cannot be taken. They must be on a least squares straight line from A to B in sapce.
EDIT:
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
Libor 'Poutnik' Stříž
2017-11-02 15:52:31 UTC
Permalink
Post by RLH
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
See above.
You did not say anything about the book.
I did observe about atoms on the light path meaning that all paths cannot be taken. They must be on a least squares straight line from A to B in sapce.
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
In case of reflections, refractions or diffractions, they need not.
And in the GR case, the straight line does not apply.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-02 17:00:25 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
Yes, it is a very good book.
See above.
You did not say anything about the book.
I did observe about atoms on the light path meaning that all paths cannot be taken. They must be on a least squares straight line from A to B in sapce.
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
In case of reflections, refractions or diffractions, they need not.
And in the GR case, the straight line does not apply.
It does if ionising radiation is indicative of the whole EMR range. Of course you can then claim that gravity bends EMR and I will defer for accurate proof as if SR ever falls then GR is moot.
Libor 'Poutnik' Stříž
2017-11-02 22:38:26 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
In case of reflections, refractions or diffractions, they need not.
And in the GR case, the straight line does not apply.
It does if ionising radiation is indicative of the whole EMR range. Of course you can then claim that gravity bends EMR and I will defer for accurate proof as if SR ever falls then GR is moot.
That is an irrelevant, uninformed note.

Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-03 00:44:15 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
In case of reflections, refractions or diffractions, they need not.
And in the GR case, the straight line does not apply.
It does if ionising radiation is indicative of the whole EMR range. Of course you can then claim that gravity bends EMR and I will defer for accurate proof as if SR ever falls then GR is moot.
That is an irrelevant, uninformed note.
Ionising radiation is a high energy example of EMR photons/wave packets.
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
Libor 'Poutnik' Stříž
2017-11-03 01:15:41 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
In case of reflections, refractions or diffractions, they need not.
And in the GR case, the straight line does not apply.
It does if ionising radiation is indicative of the whole EMR range. Of course you can then claim that gravity bends EMR and I will defer for accurate proof as if SR ever falls then GR is moot.
That is an irrelevant, uninformed note.
Ionising radiation is a high energy example of EMR photons/wave packets.
That is well known.
Post by RLH
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
Libor 'Poutnik' Stříž
2017-11-03 01:27:24 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
Let me illustrate it on the analogy of a least square approximation.

If the quadratic term is nonzero ( Gravity )
and linear approximation(SR) therefore fails,
it does not mean that the quadratic approximation(GR) fails.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-03 01:43:29 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
Let me illustrate it on the analogy of a least square approximation.
If the quadratic term is nonzero ( Gravity )
and linear approximation(SR) therefore fails,
it does not mean that the quadratic approximation(GR) fails.
Any integral of a curve or surface is only stepwise implemented in a least squares fashion from the path in the micro and macroscopic world we live in.
Libor 'Poutnik' Stříž
2017-11-03 01:59:20 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
Let me illustrate it on the analogy of a least square approximation.
If the quadratic term is nonzero ( Gravity )
and linear approximation(SR) therefore fails,
it does not mean that the quadratic approximation(GR) fails.
Any integral of a curve or surface is only stepwise implemented in a least squares fashion from the path in the micro and macroscopic world we live in.
Unrelated.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-03 02:03:38 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
Let me illustrate it on the analogy of a least square approximation.
If the quadratic term is nonzero ( Gravity )
and linear approximation(SR) therefore fails,
it does not mean that the quadratic approximation(GR) fails.
Any integral of a curve or surface is only stepwise implemented in a least squares fashion from the path in the micro and macroscopic world we live in.
Unrelated.
Unrelated to what? That is before I throw in thermal noise in as the next layer and the probability functions so derived. After that we have atomic and sub-atomic noise or motion and probably deeper on beyond than that.

How else do you think that the pure curve or surface is implemented in the real world. Magic?
Libor 'Poutnik' Stříž
2017-11-03 02:31:05 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Unrelated.
Unrelated to what?
See above.
Post by RLH
That is before I throw in thermal noise in as the next layer and the probability functions so derived. After that we have atomic and sub-atomic noise or motion and probably deeper on beyond than that.
Even more unrelated.
Post by RLH
How else do you think that the pure curve or surface is implemented in the real world. Magic?
Real world is not a computer system.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-03 08:42:27 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Real world is not a computer system.
Is that in a human or silicon sense?

https://en.wikipedia.org/wiki/Human_computer, https://www.webopedia.com/TERM/S/silicon.html,
https://www.extremetech.com/extreme/208501-what-is-silicon-and-why-are-computer-chips-made-from-it
Libor 'Poutnik' Stříž
2017-11-03 09:58:17 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Real world is not a computer system.
Is that in a human or silicon sense?
Both.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-03 12:40:35 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Real world is not a computer system.
Is that in a human or silicon sense?
Both.
If you can't tell it to a human (via conversation and paper), you can't tell it to a machine (via programming and data I/O). If you can, you can. Simples.
RLH
2017-11-03 01:41:36 UTC
Permalink
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
They must be approximated by a least squares delimited straight line from A to B in 3d/4d space.
In case of reflections, refractions or diffractions, they need not.
And in the GR case, the straight line does not apply.
It does if ionising radiation is indicative of the whole EMR range. Of course you can then claim that gravity bends EMR and I will defer for accurate proof as if SR ever falls then GR is moot.
That is an irrelevant, uninformed note.
Ionising radiation is a high energy example of EMR photons/wave packets.
That is well known.
But the implications for photon/wave packet appears not to be.
Post by Libor 'Poutnik' Stříž
Post by RLH
Post by Libor 'Poutnik' Stříž
Ionization has nothing to do with that, and in case of significant
gravity, GR takes place of SR as the general case.
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
GR is based on SR and explains it in a more general way. If SR ever falters, GT is right behind.
RLH
2017-11-03 01:46:42 UTC
Permalink
Post by RLH
GR is based on SR and explains it in a more general way. If SR ever falters, GT is right behind.
GR. Otherwise the gin will not be far away.
David (Kronos Prime) Fuller
2017-11-03 02:03:33 UTC
Permalink
For a 510998 eV photon

(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3

((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3

(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
RLH
2017-11-03 02:06:15 UTC
Permalink
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
x ≈ n.00.....0, +-.5
David (Kronos Prime) Fuller
2017-11-03 02:25:04 UTC
Permalink
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3

1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935

The factors of 161 = 1,7,23,161
David (Kronos Prime) Fuller
2017-11-03 02:34:23 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
David (Kronos Prime) Fuller
2017-11-03 02:57:31 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
((((1e-161 (m^3)) / (atomic mass units^3)) / (16 / 3)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-2
David (Kronos Prime) Fuller
2017-11-03 03:08:22 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
((((1e-161 (m^3)) / (atomic mass units^3)) / (16 / 3)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-2
1/1e-161^0.5 m^3 = 3.1622777e+80 m^3

Volume 4e+80 m^3
https://en.wikipedia.org/wiki/Observable_universe
David (Kronos Prime) Fuller
2017-11-03 04:05:01 UTC
Permalink
((((1e-161 (m^3)) / (atomic mass units^3)) / (8 * 0.6666666666)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-1
RLH
2017-11-03 08:45:45 UTC
Permalink
Post by David (Kronos Prime) Fuller
((((1e-161 (m^3)) / (atomic mass units^3)) / (8 * 0.6666666666)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-1
x ≈ n.00.....0, +-.5
RLH
2017-11-03 08:45:55 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
((((1e-161 (m^3)) / (atomic mass units^3)) / (16 / 3)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-2
1/1e-161^0.5 m^3 = 3.1622777e+80 m^3
Volume 4e+80 m^3
https://en.wikipedia.org/wiki/Observable_universe
x ≈ n.00.....0, +-.5
RLH
2017-11-03 08:46:18 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
((((1e-161 (m^3)) / (atomic mass units^3)) / (16 / 3)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-2
x ≈ n.00.....0, +-.5
RLH
2017-11-03 08:46:34 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
((((1e-161 (m^3)) / (atomic mass units^3)) / (16 / 3)) * (c^6))^(1 / 3) = 6.67410046e-11 m^3 kg^-1 s^-2
x ≈ n.00.....0, +-.5
David (Kronos Prime) Fuller
2017-11-03 02:59:13 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
G/(1e-161 m^3 / atomic mass units^3 / (16/3) * c^6 )^(1/3) = 0.999996935
RLH
2017-11-03 08:42:29 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
((16 / 3) * (((1.66054413e-27 * G) / (c^2))^3))^(1 / 3) = 2.15443469e-54 m / kg
x ≈ n.00.....0, +-.5
RLH
2017-11-03 08:42:03 UTC
Permalink
Post by David (Kronos Prime) Fuller
Post by David (Kronos Prime) Fuller
For a 510998 eV photon
(4pi / 3) * (((2 * ((510998 eV) / (c^2)) * G) / (c^2))^3) = 1.0372732e-170 m^3
((4 * pi) / 3) * (((2 * atomic mass unit * G) / (c^2))^3) = 6.28312753e-161 m^3
(((((atomic mass unit * G) / (c^2))^3) * 8)) / 1.5 = 9.99990805e-162 m^3
5.33333333333 * (1.66054413e-27 kg * G / c^2)^3 = 1e-161 m^3
1 atomic mass unit / (1.66054413e-27 kilograms) = 0.999996935
The factors of 161 = 1,7,23,161
x ≈ n.00.....0, +-.5
Libor 'Poutnik' Stříž
2017-11-03 02:02:41 UTC
Permalink
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
Ionising radiation is a high energy example of EMR photons/wave packets.
That is well known.
But the implications for photon/wave packet appears not to be.
It depends on a person.
Post by RLH
Post by Libor 'Poutnik' Stříž
Post by RLH
If SR fails in any way then GR is moot as you well know.
No, I do not, and you should know better.
GR is based on SR and explains it in a more general way. If SR ever falters, GR is right behind.
You should know better.
The more general way applies, where SR fails, because of gravity.
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-02 12:42:26 UTC
Permalink
Post by Gary Harnagel
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
But the sun interacts with all the planets in the solar system, so that
means the sun is as big as the whole solar system according to your
assertion.
I was talking about things at molecular and atomic levels. Feel free to speculate about solar system size systems yourself.
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and travel
some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
All possible paths unless I setup a detector in the middle. Then almost all paths have to go through that point as well. Unless they somehow 'know' the detector is not active before they start out or during their travel.

And so on for multiple detectors in the path, even down to 1 detector per atom traversed by the photon/wave packet.
Gary Harnagel
2017-11-02 15:19:11 UTC
Permalink
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a
trajectory.
They occupy some volume of space otherwise how do they interact with matter?
But the sun interacts with all the planets in the solar system, so that
means the sun is as big as the whole solar system according to your
assertion.
I was talking about things at molecular and atomic levels. Feel free to
speculate about solar system size systems yourself.
So you believe gravity doesn't work at molecular/atomic scales?
Electric and magnetic fields certainly do. So you're saying that a nucleus
is bigger than a whole atom because it influences orbital electrons?
Good grief! THINK!!
Post by RLH
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and
travel some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
All possible paths unless I setup a detector in the middle. Then almost all
paths have to go through that point as well.
Which changes the experiment. Thinking "logically" is useless when dealing
with the very small.

“No, no, you’re not thinking: you’re just being logical” – Niels Bohr
Post by RLH
Unless they somehow 'know' the detector is not active before they start out
or during their travel.
And so on for multiple detectors in the path, even down to 1 detector per
atom traversed by the photon/wave packet.
You can't change reality by "logic."
Matt Harry
2017-11-02 15:23:44 UTC
Permalink
Post by RLH
I was talking about things at molecular and atomic levels. Feel free to
speculate about solar system size systems yourself.
So you believe gravity doesn't work at molecular/atomic scales? Electric
and magnetic fields certainly do. So you're saying that a nucleus is
bigger than a whole atom because it influences orbital electrons?
Good grief! THINK!!
You don't have a one-to-one correspondence model of the Atom, Gigi. His
speculative model makes perfectly sense. You are implying that drawings
from the books are making any sense. Those are wrong, I can tell you for
certain.
RLH
2017-11-02 17:01:40 UTC
Permalink
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a
trajectory.
They occupy some volume of space otherwise how do they interact with matter?
But the sun interacts with all the planets in the solar system, so that
means the sun is as big as the whole solar system according to your
assertion.
I was talking about things at molecular and atomic levels. Feel free to
speculate about solar system size systems yourself.
So you believe gravity doesn't work at molecular/atomic scales?
Electric and magnetic fields certainly do. So you're saying that a nucleus
is bigger than a whole atom because it influences orbital electrons?
Good grief! THINK!!
A field is a field. How you wish to interpret the details of the interaction with matter is of no consequence to me.
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and
travel some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another. That's
REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
All possible paths unless I setup a detector in the middle. Then almost all
paths have to go through that point as well.
Which changes the experiment. Thinking "logically" is useless when dealing
with the very small.
See above about why photons/wave packets do in fact travel in a single line in space. No matter what other theory says about them.
Post by Gary Harnagel
“No, no, you’re not thinking: you’re just being logical” – Niels Bohr
Post by RLH
Unless they somehow 'know' the detector is not active before they start out
or during their travel.
And so on for multiple detectors in the path, even down to 1 detector per
atom traversed by the photon/wave packet.
You can't change reality by "logic."
You can't observe reality without logic.
Gary Harnagel
2017-11-02 17:35:43 UTC
Permalink
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they
have a trajectory.
They occupy some volume of space otherwise how do they interact with
matter?
But the sun interacts with all the planets in the solar system, so that
means the sun is as big as the whole solar system according to your
assertion.
I was talking about things at molecular and atomic levels. Feel free to
speculate about solar system size systems yourself.
So you believe gravity doesn't work at molecular/atomic scales?
Electric and magnetic fields certainly do. So you're saying that a nucleus
is bigger than a whole atom because it influences orbital electrons?
Good grief! THINK!!
A field is a field. How you wish to interpret the details of the interaction
with matter is of no consequence to me.
Hey, I'm not the one that made the stupid assertion that interaction defines
the size of a body.
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and
travel some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that
a photon takes all possible paths in going from one point to another.
That's REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
All possible paths unless I setup a detector in the middle. Then almost
all paths have to go through that point as well.
Which changes the experiment. Thinking "logically" is useless when dealing
with the very small.
See above about why photons/wave packets do in fact travel in a single line
in space. No matter what other theory says about them.
And what little gnome under a bridge gave you this marvelous insight?
"Other" theory? You he best theory we have refutes your baseless assumption.
Post by RLH
Post by Gary Harnagel
“No, no, you’re not thinking: you’re just being logical” – Niels Bohr
Post by RLH
Unless they somehow 'know' the detector is not active before they start
out or during their travel.
And so on for multiple detectors in the path, even down to 1 detector per
atom traversed by the photon/wave packet.
You can't change reality by "logic."
You can't observe reality without logic.
You can't observe reality without an open mind. If your experience defies
logic, which do you choose?

“Logic is like the sword--those who appeal to it shall perish by it.”
― Samuel Butler

One problem is that you THINK you're appealing to logic when you are only
exercising your prejudices.
RLH
2017-11-02 17:38:58 UTC
Permalink
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they
have a trajectory.
They occupy some volume of space otherwise how do they interact with
matter?
But the sun interacts with all the planets in the solar system, so that
means the sun is as big as the whole solar system according to your
assertion.
I was talking about things at molecular and atomic levels. Feel free to
speculate about solar system size systems yourself.
So you believe gravity doesn't work at molecular/atomic scales?
Electric and magnetic fields certainly do. So you're saying that a nucleus
is bigger than a whole atom because it influences orbital electrons?
Good grief! THINK!!
A field is a field. How you wish to interpret the details of the interaction
with matter is of no consequence to me.
Hey, I'm not the one that made the stupid assertion that interaction defines
the size of a body.
Consider a sphere going through a larger sphere or field.
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and
travel some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that
a photon takes all possible paths in going from one point to another.
That's REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
All possible paths unless I setup a detector in the middle. Then almost
all paths have to go through that point as well.
Which changes the experiment. Thinking "logically" is useless when dealing
with the very small.
See above about why photons/wave packets do in fact travel in a single line
in space. No matter what other theory says about them.
And what little gnome under a bridge gave you this marvelous insight?
"Other" theory? You he best theory we have refutes your baseless assumption.
Post by RLH
Post by Gary Harnagel
“No, no, you’re not thinking: you’re just being logical” – Niels Bohr
Post by RLH
Unless they somehow 'know' the detector is not active before they start
out or during their travel.
And so on for multiple detectors in the path, even down to 1 detector per
atom traversed by the photon/wave packet.
You can't change reality by "logic."
You can't observe reality without logic.
You can't observe reality without an open mind. If your experience defies
logic, which do you choose?
I choose observation.
Post by Gary Harnagel
“Logic is like the sword--those who appeal to it shall perish by it.”
― Samuel Butler
One problem is that you THINK you're appealing to logic when you are only
exercising your prejudices.
Not true. You just want to see it that way.
Gary Harnagel
2017-11-02 20:26:08 UTC
Permalink
Post by RLH
Post by Gary Harnagel
Post by RLH
A field is a field. How you wish to interpret the details of the
interaction with matter is of no consequence to me.
Hey, I'm not the one that made the stupid assertion that interaction defines
the size of a body.
Consider a sphere going through a larger sphere or field.
So is it a "larger sphere" or is it a "field"?

Your statement makes no sense.
Post by RLH
Post by Gary Harnagel
Post by RLH
You can't observe reality without logic.
You can't observe reality without an open mind. If your experience defies
logic, which do you choose?
I choose observation.
That's not what you've been choosing.
Post by RLH
Post by Gary Harnagel
“Logic is like the sword--those who appeal to it shall perish by it.”
― Samuel Butler
One problem is that you THINK you're appealing to logic when you are only
exercising your prejudices.
Not true. You just want to see it that way.
True. You just cling to your delusions.
RLH
2017-11-02 20:58:14 UTC
Permalink
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
A field is a field. How you wish to interpret the details of the
interaction with matter is of no consequence to me.
Hey, I'm not the one that made the stupid assertion that interaction defines
the size of a body.
Consider a sphere going through a larger sphere or field.
So is it a "larger sphere" or is it a "field"?
Your statement makes no sense.
Both I suspect. Depends on context.
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
You can't observe reality without logic.
You can't observe reality without an open mind. If your experience defies
logic, which do you choose?
I choose observation.
That's not what you've been choosing.
It is you know.
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
“Logic is like the sword--those who appeal to it shall perish by it.”
― Samuel Butler
One problem is that you THINK you're appealing to logic when you are only
exercising your prejudices.
Not true. You just want to see it that way.
True. You just cling to your delusions.
cf. Lateral thinking. https://en.wikipedia.org/wiki/Lateral_thinking tools 1-4.
Gary Harnagel
2017-11-02 22:05:31 UTC
Permalink
Post by RLH
Post by Gary Harnagel
Post by RLH
Consider a sphere going through a larger sphere or field.
So is it a "larger sphere" or is it a "field"?
Your statement makes no sense.
Both I suspect. Depends on context.
Still as clear as mud.
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
Post by RLH
You can't observe reality without logic.
You can't observe reality without an open mind. If your experience
defies logic, which do you choose?
I choose observation.
That's not what you've been choosing.
It is you know.
I KNOW that you've been choosing your own weird idea of "logic."
Post by RLH
Post by Gary Harnagel
Post by RLH
Post by Gary Harnagel
“Logic is like the sword--those who appeal to it shall perish by it.”
― Samuel Butler
One problem is that you THINK you're appealing to logic when you are
only exercising your prejudices.
Not true. You just want to see it that way.
True. You just cling to your delusions.
cf. Lateral thinking. https://en.wikipedia.org/wiki/Lateral_thinking tools 1-4.
You may believe you are doing that if it strokes your ego.
Darrell Vandergrift
2017-11-03 11:10:53 UTC
Permalink
Post by Gary Harnagel
Post by RLH
The have a trajectory in the sense that are created and they die and
travel some path between those 2 points.
I recommend reading QED by Richard Feynman. The mathematics says that a
photon takes all possible paths in going from one point to another.
That's REALLY hard to wrap your mind around, isn't it?
BTW, the book has very little mathematics in it since it was originally
a series of lectures for intelligent non-physicists.
This explains why no mathematics.
Odd Bodkin
2017-11-02 22:24:19 UTC
Permalink
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
They collide with it and transfer energy and momentum. Why would a
programmer think that volume is required for that?
Post by RLH
The have a trajectory in the sense that are created and they die and
travel some path between those 2 points.
--
Odd Bodkin -- maker of fine toys, tools, tables
Libor 'Poutnik' Stříž
2017-11-02 22:59:21 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
They collide with it and transfer energy and momentum. Why would a
programmer think that volume is required for that?
They transfer also the angular momentum.

Far IR photons change a rotational quantum state of molecules,
near IR phtons do that together with vibrational quantum state change
( Vibrational-rotational IR spectrum )
--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.
RLH
2017-11-03 00:42:45 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
They collide with it and transfer energy and momentum. Why would a
programmer think that volume is required for that?
How else would you describe the interaction of t2 objects. Other than by the co-incident volume of space within which they work in 1/d^2.
Odd Bodkin
2017-11-03 11:50:50 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
They collide with it and transfer energy and momentum. Why would a
programmer think that volume is required for that?
How else would you describe the interaction of t2 objects. Other than by
the co-incident volume of space within which they work in 1/d^2.
I would describe them as volumeless objects transferring momentum and
energy when they are at the same location at the same time.

Now, why would a programmer think that volume is required of the objects?
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 12:47:36 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
They collide with it and transfer energy and momentum. Why would a
programmer think that volume is required for that?
How else would you describe the interaction of t2 objects. Other than by
the co-incident volume of space within which they work in 1/d^2.
I would describe them as volumeless objects transferring momentum and
energy when they are at the same location at the same time.
How can they be volumeless? They occupy, no matter how fleetingly, some volume of space otherwise they could never interact with matter which does indeed occupy some definite volume in space. One volume MUST interact with its co-incidence or not with another volume.
Post by Odd Bodkin
Now, why would a programmer think that volume is required of the objects?
Because I don't believe in magic?
Odd Bodkin
2017-11-03 12:57:09 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
They collide with it and transfer energy and momentum. Why would a
programmer think that volume is required for that?
How else would you describe the interaction of t2 objects. Other than by
the co-incident volume of space within which they work in 1/d^2.
I would describe them as volumeless objects transferring momentum and
energy when they are at the same location at the same time.
How can they be volumeless? They occupy, no matter how fleetingly, some
volume of space otherwise they could never interact with matter which
does indeed occupy some definite volume in space.
Not so. Only a single location, a common single point, is needed for
interaction. That is the only coincident condition required.

Bearing volume means occupying MORE than one location, MORE than one point.
Post by RLH
One volume MUST interact with its co-incidence or not with another volume.
Post by Odd Bodkin
Now, why would a programmer think that volume is required of the objects?
Because I don't believe in magic?
It’s not magic. It might violate some internal rule you have made up and
believe heartily, but that’s just you. Violating your internal
preconceptions does not constitute magic.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 13:03:25 UTC
Permalink
Post by Odd Bodkin
Post by RLH
How can they be volumeless? They occupy, no matter how fleetingly, some
volume of space otherwise they could never interact with matter which
does indeed occupy some definite volume in space.
Not so. Only a single location, a common single point, is needed for
interaction. That is the only coincident condition required.
Bearing volume means occupying MORE than one location, MORE than one point.
There is no such things as a point in the real world. All things have volume. Including single spheres or distributions.
Post by Odd Bodkin
Post by RLH
One volume MUST interact with its co-incidence or not with another volume.
Post by Odd Bodkin
Now, why would a programmer think that volume is required of the objects?
Because I don't believe in magic?
It’s not magic. It might violate some internal rule you have made up and
believe heartily, but that’s just you. Violating your internal
preconceptions does not constitute magic.
It is as you sue it.
Odd Bodkin
2017-11-03 14:01:06 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
How can they be volumeless? They occupy, no matter how fleetingly, some
volume of space otherwise they could never interact with matter which
does indeed occupy some definite volume in space.
Not so. Only a single location, a common single point, is needed for
interaction. That is the only coincident condition required.
Bearing volume means occupying MORE than one location, MORE than one point.
There is no such things as a point in the real world.
That is a manifestly untrue statement. Experimental evidence clearly says
otherwise.
So now the question is about your belief in your statement and WHY you
believe it to be true.
Post by RLH
All things have volume. Including single spheres or distributions.
Post by Odd Bodkin
Post by RLH
One volume MUST interact with its co-incidence or not with another volume.
Post by Odd Bodkin
Now, why would a programmer think that volume is required of the objects?
Because I don't believe in magic?
It’s not magic. It might violate some internal rule you have made up and
believe heartily, but that’s just you. Violating your internal
preconceptions does not constitute magic.
It is as you sue it.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 16:57:33 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
How can they be volumeless? They occupy, no matter how fleetingly, some
volume of space otherwise they could never interact with matter which
does indeed occupy some definite volume in space.
Not so. Only a single location, a common single point, is needed for
interaction. That is the only coincident condition required.
Bearing volume means occupying MORE than one location, MORE than one point.
There is no such things as a point in the real world.
That is a manifestly untrue statement. Experimental evidence clearly says
otherwise.
So now the question is about your belief in your statement and WHY you
believe it to be true.
There are no points. Only close approximations to one. Even at atomic level there are no points, only probabilities.

You cannot accurately (to an infinite level) place any point in the real world. Ever. It always has to have some physical dimensions and an approximate centre.

Same goes for distance between points and the time and/or space between sample points (dT, dP). Everything is limited by the precision you use, i.e. the number of decimal place you wish to write/store. Beyond that is a mystery. Just as Nyquist said.

All analogue curves are continuous. All recording of or interaction with them, by humans or by nature, is digitised/sampled by that action. Not digitalised, digitised. That is a step wise integral of the underlying function resolved at elementary particle spacing or other, higher, measuring levels. That is the thermal chaos within which we live and work.
Odd Bodkin
2017-11-03 17:37:10 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
How can they be volumeless? They occupy, no matter how fleetingly, some
volume of space otherwise they could never interact with matter which
does indeed occupy some definite volume in space.
Not so. Only a single location, a common single point, is needed for
interaction. That is the only coincident condition required.
Bearing volume means occupying MORE than one location, MORE than one point.
There is no such things as a point in the real world.
That is a manifestly untrue statement. Experimental evidence clearly says
otherwise.
So now the question is about your belief in your statement and WHY you
believe it to be true.
There are no points. Only close approximations to one. Even at atomic
level there are no points, only probabilities.
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.

Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.

When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 17:57:48 UTC
Permalink
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the 'particle' will be within a given volume. No matter how hard we look their is Brownian, thermal, noise so that even if we were to measure it 'now' it would not be the same as 'now'.
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for government work. Not quite the same thing we are talking about
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Odd Bodkin
2017-11-03 18:19:35 UTC
Permalink
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 18:27:05 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Those are properties that make no sense unless associated with a specific mass approximately located around a particular point on a particular path at this particular instant in time.

All work is an approximation. We are c^2 worse at detecting small change in mass as we are in small changes in energy. That is such a big gap than most work is done by determining energy lost rather than mass lost.

See above about the need to attach properties to specific items. A line of movement is a series of points though. Normally called a line.
RLH
2017-11-03 18:30:24 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Those are properties that make no sense unless associated with a specific mass approximately located around a particular point on a particular path at this particular instant in time.
All work is an approximation. We are c^2 worse at detecting small change in mass as we are in small changes in energy. That is such a big gap than most work is done by determining energy lost rather than mass lost.
See above about the need to attach properties to specific items. A line of movement is a series of points though. Normally called a line.
P.S> If you would like to give me a precise and accurate constant for c we can really get down to work.
Odd Bodkin
2017-11-03 18:42:58 UTC
Permalink
Post by RLH
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Those are properties that make no sense unless associated with a
specific mass approximately located around a particular point on a
particular path at this particular instant in time.
All work is an approximation. We are c^2 worse at detecting small change
in mass as we are in small changes in energy. That is such a big gap
than most work is done by determining energy lost rather than mass lost.
See above about the need to attach properties to specific items. A line
of movement is a series of points though. Normally called a line.
P.S> If you would like to give me a precise and accurate constant for c
we can really get down to work.
And why can you not google it? It is a nine-digit integer in meters per
second. Note that when I say it is an integer, that means all the places
to the right of the decimal point are zero. It is therefore as precise and
as accurate as you could ask for. It’s as precise as the number 42.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 21:57:52 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Those are properties that make no sense unless associated with a
specific mass approximately located around a particular point on a
particular path at this particular instant in time.
All work is an approximation. We are c^2 worse at detecting small change
in mass as we are in small changes in energy. That is such a big gap
than most work is done by determining energy lost rather than mass lost.
See above about the need to attach properties to specific items. A line
of movement is a series of points though. Normally called a line.
P.S> If you would like to give me a precise and accurate constant for c
we can really get down to work.
And why can you not google it? It is a nine-digit integer in meters per
second. Note that when I say it is an integer, that means all the places
to the right of the decimal point are zero. It is therefore as precise and
as accurate as you could ask for. It’s as precise as the number 42.
9 digits! Is that all you've got? And how accurate is the second and meter also? What error band/volume does it now have, overall?

Looks like we have a probability/uncertainty 'volume' right there.

That would be 42.000......0, +.....5, -....5 to you. Integers are in reality truncated/rounded floats both in computing and in maths and floats are a number range of very long integers with imprecision and uncertainty built in!

All constants and variables in an equation can be replaced by a 1.000......0, +.5, -.5 which will create a unit dimensioned space and scale with a raw uncertainly built in. Better constant approximation can be found by examining the next few digits below the precision you are using. The precision you choose sets the accuracy you can then obtain. Practical noise, cone angle and error limits what you can require or determine.

I recognise that there is no such thing as absolute size, absolute distance, absolute position, absolute precision, absolute accuracy, zero errors and zero noise in anything we do. I think Newton did also. You seem to want to ignore them just because you are 'pure'. 

Another couple of things for you to think about.

Given that the ratio of the number of atoms encountered in a few milliseconds in a relatively thick gas in the atmosphere compared to a few tens to thousands of light years in the near vacuum that is inter-stella and inter galactic space is probably very variable. What is to stop red shift as being nothing more than the same thing we see at sunset and sunrise compared to noon?

Also, Space and Time as we normally use them are 2 sides of the same thing.

I can say "I take 1 pace forward per (1) second" or "It takes me 1 second for each (1) pace forward". They are identical in meaning and effect.
Odd Bodkin
2017-11-03 22:44:05 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an
approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Those are properties that make no sense unless associated with a
specific mass approximately located around a particular point on a
particular path at this particular instant in time.
All work is an approximation. We are c^2 worse at detecting small change
in mass as we are in small changes in energy. That is such a big gap
than most work is done by determining energy lost rather than mass lost.
See above about the need to attach properties to specific items. A line
of movement is a series of points though. Normally called a line.
P.S> If you would like to give me a precise and accurate constant for c
we can really get down to work.
And why can you not google it? It is a nine-digit integer in meters per
second. Note that when I say it is an integer, that means all the places
to the right of the decimal point are zero. It is therefore as precise and
as accurate as you could ask for. It’s as precise as the number 42.
9 digits! Is that all you've got?
Please pay attention. It is 299792458.00000000000000000000... m/s. It is an
exact integer, with a precision of an infinite number of digits.
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No. There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.

From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-03 22:58:13 UTC
Permalink
Post by Odd Bodkin
Please pay attention. It is 299792458.00000000000000000000... m/s. It is an
exact integer, with a precision of an infinite number of digits.
Wrong.

"After centuries of increasingly precise measurements, in 1975 the speed of light was known to be299792458 m/s (186,282 mi/s) with a measurement uncertainty of 4 parts per billion"
https://en.wikipedia.org/wiki/Speed_of_light

I'm sure you can find a more scientific reference. Nothing is precise. Everything comes with error bars.
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An uncertainty if you will,
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No. There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that goes for paper and computer.
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
RLH
2017-11-03 23:06:23 UTC
Permalink
Post by RLH
Sure. But is that the only way that light is reddened? That and Doppler.
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
I should add that the hydrogen absorption line is a hole in our vision. It stops us seeing through that particular part of the spectrum untouched by 'vacuum' it passes though along the way.
Odd Bodkin
2017-11-04 00:04:11 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Please pay attention. It is 299792458.00000000000000000000... m/s. It is an
exact integer, with a precision of an infinite number of digits.
Wrong.
"After centuries of increasingly precise measurements, in 1975 the speed
of light was known to be299792458 m/s (186,282 mi/s) with a measurement
uncertainty of 4 parts per billion"
https://en.wikipedia.org/wiki/Speed_of_light
I'm sure you can find a more scientific reference. Nothing is precise.
Everything comes with error bars.
From the very same article you cited. The first paragraph of said article
in fact:
“The speed of light in vacuum, commonly denoted c, is a universal physical
constant important in many areas of physics. Its exact value is 299,792,458
metres per second (approximately 3.00×108 m/s, or 186,282 mi/s); it is
exact because the unit of length, the metre, is defined from this constant
and the international standard for time.[2]”

You ignore things you don’t like to see?
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No. There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-04 02:04:48 UTC
Permalink
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Please pay attention. It is 299792458.00000000000000000000... m/s. It is an
exact integer, with a precision of an infinite number of digits.
Wrong.
"After centuries of increasingly precise measurements, in 1975 the speed
of light was known to be299792458 m/s (186,282 mi/s) with a measurement
uncertainty of 4 parts per billion"
https://en.wikipedia.org/wiki/Speed_of_light
I'm sure you can find a more scientific reference. Nothing is precise.
Everything comes with error bars.
From the very same article you cited. The first paragraph of said article
“The speed of light in vacuum, commonly denoted c, is a universal physical
constant important in many areas of physics. Its exact value is 299,792,458
metres per second (approximately 3.00×108 m/s, or 186,282 mi/s); it is
exact because the unit of length, the metre, is defined from this constant
and the international standard for time.[2]”
You ignore things you don’t like to see?
Did you ignore things you didn't like as well. See that meters per second? How about in micro-meters and/or micro-second or even pico levels. How accurate are your constants now? How about that measurement uncertainty of only 4 parts per billion? That's only 10^9 or so.

"The metre is defined as the length of the path travelled by light in a vacuum in 1/299792458 seconds" Not precisely, approximately. Certainly not at 10^-9 levels.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Did I say it did? I think not. I did say that it would lie inside that volume of uncertainty somewhere, nothing more.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No.  There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Oh so easy you are.

If I have 64 bit integer computing I can either add the next 64 bits to the right or to the left of 0 to increase the appropriate LHS/RHS sides to 128 bit.

If I don't move my 0 centre, I end up with fixed point, 128 bit, 0 centred computer. With a range from +2^63 to -2^-63 without overflow or loss of precision. That's a bit bigger than 10^9!

Or I can live with my imaginary 64 bit, 0 centred fixed bit with a range of +2^31 to -2^-31 without overflow or loss of precision. or ±231−1 as some would like it

2,147,483,647 compared to 299,792,458 meters/second seems a reasonable compromise. Though it can be range adjusted if you don't want the high or low ranges to get to pico second or thousands of light years as required.

We could just pivot around ...0001.0000... if that makes things easier.

I can either increase my x or my 1/x or both in fixed point (which incidentally is the most effective way you can make use of your bits with full precision) as I decide to move my 0 centre around.

P.S. If I don't move my 0 when I add to the RHS then I can fill in the new bits with 0, 1 or random noise as you wish for the extension to your existing integers if you like, NaN down there makes things complicated.. 
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
 
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Did I say it was? But what about Compton scattering? https://en.wikipedia.org/wiki/Compton_scattering
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
I know you have a cool name for it.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
But I persevere with yours.

Have you ever considered the x space of volume doubling against the 1/x case of the volume halving balanced around a unit volume of 1?
Odd Bodkin
2017-11-04 02:22:54 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Please pay attention. It is 299792458.00000000000000000000... m/s. It is an
exact integer, with a precision of an infinite number of digits.
Wrong.
"After centuries of increasingly precise measurements, in 1975 the speed
of light was known to be299792458 m/s (186,282 mi/s) with a measurement
uncertainty of 4 parts per billion"
https://en.wikipedia.org/wiki/Speed_of_light
I'm sure you can find a more scientific reference. Nothing is precise.
Everything comes with error bars.
From the very same article you cited. The first paragraph of said article
“The speed of light in vacuum, commonly denoted c, is a universal physical
constant important in many areas of physics. Its exact value is 299,792,458
metres per second (approximately 3.00×108 m/s, or 186,282 mi/s); it is
exact because the unit of length, the metre, is defined from this constant
and the international standard for time.[2]”
You ignore things you don’t like to see?
Did you ignore things you didn't like as well. See that meters per second?
Yes I do. Do you see where it says the length of the meter is DEFINED from
this constant and the standard for time?
Post by RLH
How about in micro-meters and/or micro-second or even pico levels.
The speed of light is EXACTLY 299792458 picometers per picosecond.
It is also exactly 299792458 attometers per attosecond.
Post by RLH
How accurate are your constants now? How about that measurement
uncertainty of only 4 parts per billion? That's only 10^9 or so.
There is no longer any measurement uncertainty in the speed of light. What
part of “exact” do you not comprehend?
Post by RLH
"The metre is defined as the length of the path travelled by light in a
vacuum in 1/299792458 seconds" Not precisely, approximately. Certainly not at 10^-9 levels.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An
uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Did I say it did? I think not. I did say that it would lie inside that
volume of uncertainty somewhere, nothing more.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No.  There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Oh so easy you are.
If I have 64 bit integer computing I can either add the next 64 bits to
the right or to the left of 0 to increase the appropriate LHS/RHS sides to 128 bit.
If I don't move my 0 centre, I end up with fixed point, 128 bit, 0
centred computer. With a range from +2^63 to -2^-63 without overflow or
loss of precision. That's a bit bigger than 10^9!
Or I can live with my imaginary 64 bit, 0 centred fixed bit with a range
of +2^31 to -2^-31 without overflow or loss of precision. or ±231−1 as some would like it
2,147,483,647 compared to 299,792,458 meters/second seems a reasonable
compromise. Though it can be range adjusted if you don't want the high or
low ranges to get to pico second or thousands of light years as required.
We could just pivot around ...0001.0000... if that makes things easier.
I can either increase my x or my 1/x or both in fixed point (which
incidentally is the most effective way you can make use of your bits with
full precision) as I decide to move my 0 centre around.
P.S. If I don't move my 0 when I add to the RHS then I can fill in the
new bits with 0, 1 or random noise as you wish for the extension to your
existing integers if you like, NaN down there makes things complicated.. 
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
 
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Did I say it was? But what about Compton
scattering? https://en.wikipedia.org/wiki/Compton_scattering
Compton scattering does not preserve the spacing of the absorption lines.
Doppler does. What is observed from stars and galaxies is unambiguously
from relativistic Doppler.
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
I know you have a cool name for it.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
But I persevere with yours.
Perhaps because you crave the attention.
Post by RLH
Have you ever considered the x space of volume doubling against the 1/x
case of the volume halving balanced around a unit volume of 1?
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-04 02:31:05 UTC
Permalink
Post by Odd Bodkin
Yes I do. Do you see where it says the length of the meter is DEFINED from
this constant and the standard for time?
To what degree of precision? For both length and time? Currently we are at meters /second. We can onl 'see' that far.
Post by Odd Bodkin
Post by RLH
How about in micro-meters and/or micro-second or even pico levels.
The speed of light is EXACTLY 299792458 picometers per picosecond.
It is also exactly 299792458 attometers per attosecond.
The speed of light is not EXACTLY 299792458 picometers per second though.
Post by Odd Bodkin
Post by RLH
How accurate are your constants now? How about that measurement
uncertainty of only 4 parts per billion? That's only 10^9 or so.
There is no longer any measurement uncertainty in the speed of light. What
part of “exact” do you not comprehend?
What part of measurement and calibration error don't you get?
Post by Odd Bodkin
Post by RLH
"The metre is defined as the length of the path travelled by light in a
vacuum in 1/299792458 seconds" Not precisely, approximately. Certainly not at 10^-9 levels.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An
uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Did I say it did? I think not. I did say that it would lie inside that
volume of uncertainty somewhere, nothing more.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No.  There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Oh so easy you are.
If I have 64 bit integer computing I can either add the next 64 bits to
the right or to the left of 0 to increase the appropriate LHS/RHS sides to 128 bit.
If I don't move my 0 centre, I end up with fixed point, 128 bit, 0
centred computer. With a range from +2^63 to -2^-63 without overflow or
loss of precision. That's a bit bigger than 10^9!
Or I can live with my imaginary 64 bit, 0 centred fixed bit with a range
of +2^31 to -2^-31 without overflow or loss of precision. or ±231−1 as some would like it
2,147,483,647 compared to 299,792,458 meters/second seems a reasonable
compromise. Though it can be range adjusted if you don't want the high or
low ranges to get to pico second or thousands of light years as required.
We could just pivot around ...0001.0000... if that makes things easier.
I can either increase my x or my 1/x or both in fixed point (which
incidentally is the most effective way you can make use of your bits with
full precision) as I decide to move my 0 centre around.
P.S. If I don't move my 0 when I add to the RHS then I can fill in the
new bits with 0, 1 or random noise as you wish for the extension to your
existing integers if you like, NaN down there makes things complicated.. 
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
 
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Did I say it was? But what about Compton
scattering? https://en.wikipedia.org/wiki/Compton_scattering
Compton scattering does not preserve the spacing of the absorption lines.
Doppler does. What is observed from stars and galaxies is unambiguously
from relativistic Doppler.
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
I know you have a cool name for it.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
But I persevere with yours.
Perhaps because you crave the attention.
Nope. Not me.
Post by Odd Bodkin
Post by RLH
Have you ever considered the x space of volume doubling against the 1/x
case of the volume halving balanced around a unit volume of 1?
No answer?
RLH
2017-11-04 02:36:50 UTC
Permalink
EDIT:

The speed of light is not EXACTLY 299792458000...0 picometers per second though.
Odd Bodkin
2017-11-04 02:40:57 UTC
Permalink
Post by RLH
The speed of light is not EXACTLY 299792458000...0 picometers per second though.
It is exactly 299792458000000000000 picometers per second.
--
Odd Bodkin -- maker of fine toys, tools, tables
Odd Bodkin
2017-11-04 02:39:37 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Yes I do. Do you see where it says the length of the meter is DEFINED from
this constant and the standard for time?
To what degree of precision? For both length and time? Currently we are
at meters /second. We can onl 'see' that far.
Post by Odd Bodkin
Post by RLH
How about in micro-meters and/or micro-second or even pico levels.
The speed of light is EXACTLY 299792458 picometers per picosecond.
It is also exactly 299792458 attometers per attosecond.
The speed of light is not EXACTLY 299792458 picometers per second though.
It is exactly 299792458000000000000 picometers per second.
Post by RLH
Post by Odd Bodkin
Post by RLH
How accurate are your constants now? How about that measurement
uncertainty of only 4 parts per billion? That's only 10^9 or so.
There is no longer any measurement uncertainty in the speed of light. What
part of “exact” do you not comprehend?
What part of measurement and calibration error don't you get?
You can scowl and deny that c is exact until you are blue in the face.
Wikipedia is correct here. It is exact.
Post by RLH
Post by Odd Bodkin
Post by RLH
"The metre is defined as the length of the path travelled by light in a
vacuum in 1/299792458 seconds" Not precisely, approximately. Certainly
not at 10^-9 levels.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An
uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Did I say it did? I think not. I did say that it would lie inside that
volume of uncertainty somewhere, nothing more.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No.  There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Oh so easy you are.
If I have 64 bit integer computing I can either add the next 64 bits to
the right or to the left of 0 to increase the appropriate LHS/RHS sides to 128 bit.
If I don't move my 0 centre, I end up with fixed point, 128 bit, 0
centred computer. With a range from +2^63 to -2^-63 without overflow or
loss of precision. That's a bit bigger than 10^9!
Or I can live with my imaginary 64 bit, 0 centred fixed bit with a range
of +2^31 to -2^-31 without overflow or loss of precision. or ±231−1 as some would like it
2,147,483,647 compared to 299,792,458 meters/second seems a reasonable
compromise. Though it can be range adjusted if you don't want the high or
low ranges to get to pico second or thousands of light years as required.
We could just pivot around ...0001.0000... if that makes things easier.
I can either increase my x or my 1/x or both in fixed point (which
incidentally is the most effective way you can make use of your bits with
full precision) as I decide to move my 0 centre around.
P.S. If I don't move my 0 when I add to the RHS then I can fill in the
new bits with 0, 1 or random noise as you wish for the extension to your
existing integers if you like, NaN down there makes things complicated.. 
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
 
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Did I say it was? But what about Compton
scattering? https://en.wikipedia.org/wiki/Compton_scattering
Compton scattering does not preserve the spacing of the absorption lines.
Doppler does. What is observed from stars and galaxies is unambiguously
from relativistic Doppler.
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
I know you have a cool name for it.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
But I persevere with yours.
Perhaps because you crave the attention.
Nope. Not me.
Post by Odd Bodkin
Post by RLH
Have you ever considered the x space of volume doubling against the 1/x
case of the volume halving balanced around a unit volume of 1?
No answer?
Not worth one.
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-04 02:43:32 UTC
Permalink
Post by Odd Bodkin
It is exactly 299792458000000000000 picometers per second.
Now you are showing your ignorance. There is a stated error of 1 in 10^9 right in there in wiki. That means that anything with a range larger than that is thermal noise (or truncated in your case).
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
How accurate are your constants now? How about that measurement
uncertainty of only 4 parts per billion? That's only 10^9 or so.
There is no longer any measurement uncertainty in the speed of light. What
part of “exact” do you not comprehend?
What part of measurement and calibration error don't you get?
You can scowl and deny that c is exact until you are blue in the face.
Wikipedia is correct here. It is exact.
Wiki also says that there is measurement errors.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
"The metre is defined as the length of the path travelled by light in a
vacuum in 1/299792458 seconds" Not precisely, approximately. Certainly
not at 10^-9 levels.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An
uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Did I say it did? I think not. I did say that it would lie inside that
volume of uncertainty somewhere, nothing more.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No.  There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Oh so easy you are.
If I have 64 bit integer computing I can either add the next 64 bits to
the right or to the left of 0 to increase the appropriate LHS/RHS sides to 128 bit.
If I don't move my 0 centre, I end up with fixed point, 128 bit, 0
centred computer. With a range from +2^63 to -2^-63 without overflow or
loss of precision. That's a bit bigger than 10^9!
Or I can live with my imaginary 64 bit, 0 centred fixed bit with a range
of +2^31 to -2^-31 without overflow or loss of precision. or ±231−1 as some would like it
2,147,483,647 compared to 299,792,458 meters/second seems a reasonable
compromise. Though it can be range adjusted if you don't want the high or
low ranges to get to pico second or thousands of light years as required.
We could just pivot around ...0001.0000... if that makes things easier.
I can either increase my x or my 1/x or both in fixed point (which
incidentally is the most effective way you can make use of your bits with
full precision) as I decide to move my 0 centre around.
P.S. If I don't move my 0 when I add to the RHS then I can fill in the
new bits with 0, 1 or random noise as you wish for the extension to your
existing integers if you like, NaN down there makes things complicated.. 
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
 
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Did I say it was? But what about Compton
scattering? https://en.wikipedia.org/wiki/Compton_scattering
Compton scattering does not preserve the spacing of the absorption lines.
Doppler does. What is observed from stars and galaxies is unambiguously
from relativistic Doppler.
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
I know you have a cool name for it.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
But I persevere with yours.
Perhaps because you crave the attention.
Nope. Not me.
Post by Odd Bodkin
Post by RLH
Have you ever considered the x space of volume doubling against the 1/x
case of the volume halving balanced around a unit volume of 1?
No answer?
Not worth one.
--
Odd Bodkin -- maker of fine toys, tools, tables
Odd Bodkin
2017-11-04 03:05:11 UTC
Permalink
Post by RLH
Post by Odd Bodkin
It is exactly 299792458000000000000 picometers per second.
Now you are showing your ignorance. There is a stated error of 1 in 10^9
right in there in wiki.
Read the date of that result. Now read the date of the standard which set
the speed of light to be exact.

So not only are you unable to do 5th grade algebra, you cannot read an
encyclopedia article at the 5th grade level? What part of “exact” are you
having problems understanding?
Post by RLH
That means that anything with a range larger than that is thermal noise
(or truncated in your case).
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
How accurate are your constants now? How about that measurement
uncertainty of only 4 parts per billion? That's only 10^9 or so.
There is no longer any measurement uncertainty in the speed of light. What
part of “exact” do you not comprehend?
What part of measurement and calibration error don't you get?
You can scowl and deny that c is exact until you are blue in the face.
Wikipedia is correct here. It is exact.
Wiki also says that there is measurement errors.
Were. Pay attention. If you read the article COMPLETELY the apparent
conflict will be resolved for you. I cannot Read for you. You have to do
that yourself.
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
"The metre is defined as the length of the path travelled by light in a
vacuum in 1/299792458 seconds" Not precisely, approximately. Certainly
not at 10^-9 levels.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
And how accurate is the second and meter also? What error band/volume
does it now have, overall?
Looks like we have a probability/uncertainty 'volume' right there.
I’ll repeat: uncertainty in a position does not constitute volume. If I
tell you that the top of Mount Everest has an elevation of 29029’ +/- 2’,
this does not mean that the tip of the mountain occupies the space between
29027’ and 29031’.
It means we cannot be more accurate than saying 29029’ +/- 2’. An
uncertainty if you will,
Completely right. And so this uncertainty does not indicate the object has
a volume of that uncertainty magnitude
Did I say it did? I think not. I did say that it would lie inside that
volume of uncertainty somewhere, nothing more.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
That would be 42.000......0, +.....5, -....5 to you.
No.  There IS NO LSB for an integer. You can inaccurately represent that
number with an LSB in a computer, but that is a limitation of your
imperfect implementation and not a limitation on the precision of the
number. Don’t confuse the limits of your implementation with the limits of
reality.
LSDigit if you really must, I did define it thus previously. And that
goes for paper and computer.
And an integer is EXACT. Even if you cannot implement that on a computer.
Oh so easy you are.
If I have 64 bit integer computing I can either add the next 64 bits to
the right or to the left of 0 to increase the appropriate LHS/RHS sides to 128 bit.
If I don't move my 0 centre, I end up with fixed point, 128 bit, 0
centred computer. With a range from +2^63 to -2^-63 without overflow or
loss of precision. That's a bit bigger than 10^9!
Or I can live with my imaginary 64 bit, 0 centred fixed bit with a range
of +2^31 to -2^-31 without overflow or loss of precision. or ±231−1
as some would like it
2,147,483,647 compared to 299,792,458 meters/second seems a reasonable
compromise. Though it can be range adjusted if you don't want the high or
low ranges to get to pico second or thousands of light years as required.
We could just pivot around ...0001.0000... if that makes things easier.
I can either increase my x or my 1/x or both in fixed point (which
incidentally is the most effective way you can make use of your bits with
full precision) as I decide to move my 0 centre around.
P.S. If I don't move my 0 when I add to the RHS then I can fill in the
new bits with 0, 1 or random noise as you wish for the extension to your
existing integers if you like, NaN down there makes things complicated.. 
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Integers are in reality truncated/rounded floats both in computing and in
maths and floats are a number range of very long integers with
imprecision and uncertainty built in!
All constants and variables in an equation can be replaced by a
1.000......0, +.5, -.5 which will create a unit dimensioned space and
scale with a raw uncertainly built in. Better constant approximation can
be found by examining the next few digits below the precision you are
using. The precision you choose sets the accuracy you can then obtain.
Practical noise, cone angle and error limits what you can require or determine.
I recognise that there is no such thing as absolute size, absolute
distance, absolute position, absolute precision, absolute accuracy, zero
errors and zero noise in anything we do. I think Newton did also. You
seem to want to ignore them just because you are 'pure'. 
Another couple of things for you to think about.
Given that the ratio of the number of atoms encountered in a few
milliseconds in a relatively thick gas in the atmosphere compared to a
few tens to thousands of light years in the near vacuum that is
inter-stella and inter galactic space is probably very variable. What is
to stop red shift as being nothing more than the same thing we see at
sunset and sunrise compared to noon?
The red in a sunset is what’s left over from the sideways scattering of
bluer light.
No kidding.
 
Post by Odd Bodkin
What you will notice with the light in a reddened sky is that there is
still a hydrogen absorption line exactly where you see it from a
terrestrial source. In other words, the light is reddened but not shifted.
Sure. But is that the only way that light is reddened? That and Doppler.
Sunset is not from Doppler for the reason JUST DESCRIBED.
Did I say it was? But what about Compton
scattering? https://en.wikipedia.org/wiki/Compton_scattering
Compton scattering does not preserve the spacing of the absorption lines.
Doppler does. What is observed from stars and galaxies is unambiguously
from relativistic Doppler.
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
From stars and galaxies, the absorption lines are actually displaced to
longer wavelengths. Thus it is more than just reddening. It is a redSHIFT.
I’m dismayed that you did not know this.
I did. And that is Doppler not Relativity.
Relativistic Doppler. Look it up.
I know you have a cool name for it.
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
Post by RLH
Also, Space and Time as we normally use them are 2 sides of the same thing.
I can say "I take 1 pace forward per (1) second" or "It takes me 1 second
for each (1) pace forward". They are identical in meaning and effect.
Didn't have a reply for that?
Not everything you say is worth it.
But I persevere with yours.
Perhaps because you crave the attention.
Nope. Not me.
Post by Odd Bodkin
Post by RLH
Have you ever considered the x space of volume doubling against the 1/x
case of the volume halving balanced around a unit volume of 1?
No answer?
Not worth one.
--
Odd Bodkin -- maker of fine toys, tools, tables
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-04 03:10:27 UTC
Permalink
On Saturday, November 4, 2017 at 3:05:15 AM UTC, Odd Bodkin wrote:
snip

Now think very carefully. It is only exact because the definitions are circular. One in terms of the other. Of course it is exact. The question is, should it be so or are we confusing ourselves?
Odd Bodkin
2017-11-04 03:17:40 UTC
Permalink
Post by RLH
snip
Now think very carefully. It is only exact because the definitions are
circular. One in terms of the other. Of course it is exact. The question
is, should it be so or are we confusing ourselves?
Perhaps you should ask why they chose it this way rather than assume the
people making that choice are missing something.

I’ll reiterate that you had to ask for what the value of c is, rather than
searching for it yourself. Then you mistakenly took the value of c to have
some uncertainty when it does not, by construction, and you didn’t bother
to read to discover your mistake. Now you are assuming that a bad idea has
been pursued, and you still have the opportunity to read before jumping to
an idiotic conclusion. What’s your choice? Do you learn from mistakes?
--
Odd Bodkin -- maker of fine toys, tools, tables
RLH
2017-11-04 08:26:40 UTC
Permalink
Post by Odd Bodkin
Post by RLH
snip
Now think very carefully. It is only exact because the definitions are
circular. One in terms of the other. Of course it is exact. The question
is, should it be so or are we confusing ourselves?
Perhaps you should ask why they chose it this way rather than assume the
people making that choice are missing something.
I’ll reiterate that you had to ask for what the value of c is, rather than
searching for it yourself. Then you mistakenly took the value of c to have
some uncertainty when it does not, by construction, and you didn’t bother
to read to discover your mistake. Now you are assuming that a bad idea has
been pursued, and you still have the opportunity to read before jumping to
an idiotic conclusion. What’s your choice? Do you learn from mistakes?
So tell me oh knowledgeable one, exactly how long are the path beams in a LIGO detector and how long does it take photons to travel that length. 4.000... Kilometres and its reciprocal?

"Based on current models of astronomical events, and the predictions of the general theory of relativity, gravitational waves that originate tens of millions of light years from Earth are expected to distort the 4 kilometre mirror spacing by about 10^−18 metres, less than one-thousandth the charge diameter of a proton. Equivalently, this is a relative change in distance of approximately one part in 10^21".

Reasonably accurate. But only reasonably so. We want absolute precision. You tell me we can have it. Where is it?
RLH
2017-11-04 09:06:52 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
snip
Now think very carefully. It is only exact because the definitions are
circular. One in terms of the other. Of course it is exact. The question
is, should it be so or are we confusing ourselves?
Perhaps you should ask why they chose it this way rather than assume the
people making that choice are missing something.
I’ll reiterate that you had to ask for what the value of c is, rather than
searching for it yourself. Then you mistakenly took the value of c to have
some uncertainty when it does not, by construction, and you didn’t bother
to read to discover your mistake. Now you are assuming that a bad idea has
been pursued, and you still have the opportunity to read before jumping to
an idiotic conclusion. What’s your choice? Do you learn from mistakes?
So tell me oh knowledgeable one, exactly how long are the path beams in a LIGO detector and how long does it take photons to travel that length. 4.000... Kilometres and its reciprocal?
"Based on current models of astronomical events, and the predictions of the general theory of relativity, gravitational waves that originate tens of millions of light years from Earth are expected to distort the 4 kilometre mirror spacing by about 10^−18 metres, less than one-thousandth the charge diameter of a proton. Equivalently, this is a relative change in distance of approximately one part in 10^21".
Reasonably accurate. But only reasonably so. We want absolute precision. You tell me we can have it. Where is it?
I live in a world were only the first 32 or 64 or 128..... bits of Pi in binary are required.

That's 3.
1415
9265
3589
7932
3846
2643
3832
7950
2884
1971
6939
9375
1058
2097
4944
59(2 +.0, - .3)

for Q1.63 (approximately)
RLH
2017-11-04 09:08:59 UTC
Permalink
EDIT:

I live in a world were only the first 31 or 63 or 127..... bits of Pi in binary are required.
RLH
2017-11-04 09:11:34 UTC
Permalink
Post by RLH
I live in a world were only the first 31 or 63 or 127..... bits of Pi in binary are required.
I live in a world were only the first 31 or 63 or 127..... bits of Pi in binary or digits in decimal are required.
RLH
2017-11-04 09:24:20 UTC
Permalink
Any other constants you would like in there? How about a good definition for c?
RLH
2017-11-04 09:22:00 UTC
Permalink
Post by RLH
Post by RLH
Post by Odd Bodkin
Post by RLH
snip
Now think very carefully. It is only exact because the definitions are
circular. One in terms of the other. Of course it is exact. The question
is, should it be so or are we confusing ourselves?
Perhaps you should ask why they chose it this way rather than assume the
people making that choice are missing something.
I’ll reiterate that you had to ask for what the value of c is, rather than
searching for it yourself. Then you mistakenly took the value of c to have
some uncertainty when it does not, by construction, and you didn’t bother
to read to discover your mistake. Now you are assuming that a bad idea has
been pursued, and you still have the opportunity to read before jumping to
an idiotic conclusion. What’s your choice? Do you learn from mistakes?
So tell me oh knowledgeable one, exactly how long are the path beams in a LIGO detector and how long does it take photons to travel that length. 4.000... Kilometres and its reciprocal?
"Based on current models of astronomical events, and the predictions of the general theory of relativity, gravitational waves that originate tens of millions of light years from Earth are expected to distort the 4 kilometre mirror spacing by about 10^−18 metres, less than one-thousandth the charge diameter of a proton. Equivalently, this is a relative change in distance of approximately one part in 10^21".
Reasonably accurate. But only reasonably so. We want absolute precision. You tell me we can have it. Where is it?
I live in a world were only the first 32 or 64 or 128..... bits of Pi in binary are required.
That's 3.
1415
9265
3589
7932
3846
2643
3832
7950
2884
1971
6939
9375
1058
2097
4944
59(2 +.0, - .3)
for Q1.63 (approximately)
Sqrt(2) =

That's 1.
4141
4141
4141
4141
4141
4141
4141
4141
4141
4141
4141
4141
4141
4141
4141
41(4 +.1, - .0)

for Q1.63 (approximately)
m***@wp.pl
2017-11-04 07:07:06 UTC
Permalink
Post by Odd Bodkin
“The speed of light in vacuum, commonly denoted c, is a universal physical
constant important in many areas of physics. Its exact value is 299,792,458
metres per second (approximately 3.00×108 m/s, or 186,282 mi/s); it is
exact because the unit of length, the metre, is defined from this constant
and the international standard for time.[2]”
Too bad that your General Shit rejects constant speed of
light and according to it your definitione is inconsistent.

Too bad also that no sane people obey your moronic
"standard for time", as you can check at GPS.
Odd Bodkin
2017-11-03 18:39:23 UTC
Permalink
Post by RLH
Post by Odd Bodkin
Post by RLH
Post by Odd Bodkin
I’m sorry but you are simply misinformed and at this point just repeating
your unjustified preconceptions.
Go on then. Define for me what a point is in the physical sense.
A physical thing can have mass, charge, spin, baryonic number, and a host
of other properties without having any volume. There is nothing about any
of those properties that requires volume, even conceptually.
Post by RLH
Post by Odd Bodkin
Post by RLH
You cannot accurately (to an infinite level) place any point in the real
world. Ever. It always has to have some physical dimensions and an approximate centre.
Having an uncertainty on a location is not the same thing as having a
volume. Conversely, being volumeless and pointlike does not imply being
able to locate it with perfect precision.
It is precisely like a volume. There is a given probability that the
'particle' will be within a given volume. No matter how hard we look
their is Brownian, thermal, noise so that even if we were to measure it
'now' it would not be the same as 'now'.
Sorry, but that is NOT the same thing. What you are doing is measuring a
distribution of its locations as measured at different times. This is much
different than being able, at one snapshot of time, to identify a point on
the boundary of the object and a different point that is unambiguously in
the interior of the object.
Post by RLH
Post by Odd Bodkin
Likewise, Newton’s first law about constant motion does not hinge on
whether there is a measurement protocol with infinite precision to
establish that constancy numerically. This is a basic disconnect you have
about comparing experimental measurements against physical models.
Sure we work with approximate summaries instead. Good enough for
government work. Not quite the same thing we are talking about
Newton’s first law is not an approximation.
Post by RLH
Post by Odd Bodkin
When you can come up with a PHYSICAL argument about why you think things
must have volume, then we can talk further.
How else do you describe the existence and location of any particle?
I’ve already told you. A particle has many measurable properties which are
not dependent on volume. Then all that is needed is a location. A location
is a SINGLE point, not a range of points.
Post by RLH
Post by Odd Bodkin
Post by RLH
Same goes for distance between points and the time and/or space between
sample points (dT, dP). Everything is limited by the precision you use,
i.e. the number of decimal place you wish to write/store. Beyond that is
a mystery. Just as Nyquist said.
All analogue curves are continuous. All recording of or interaction with
them, by humans or by nature, is digitised/sampled by that action. Not
digitalised, digitised. That is a step wise integral of the underlying
function resolved at elementary particle spacing or other, higher,
measuring levels. That is the thermal chaos within which we live and work.
Those are properties that make no sense unless associated with a specific
mass approximately located around a particular point on a particular path
at this particular instant in time.
Why do you insist these make no sense unless in your preconceived world
view? You still have not presented any logical argument that volume is
necessitated by these properties, other than your complaint that you can’t
conceive it any other way. That’s not an argument, it’s an overly
constrained imagination.
Post by RLH
All work is an approximation. We are c^2 worse at detecting small change
in mass as we are in small changes in energy. That is such a big gap than
most work is done by determining energy lost rather than mass lost.
No. The value of c is an accident of choice of units. It’s nothing more
than a conversion factor.
If I gave you the task of measuring the length of a football pitch and I
gave you the choice of measuring it in millimeters or in feet, would you
say that because feet are bigger, it’s impossible to measure the pitch in
feet to the same precision as you could in millimeters?? No. The only thing
that changes is where the decimal point appears in a comparably long string
of numbers.

It is no harder to measure the energy of something to the same precision
you measure the mass of something.
Post by RLH
See above about the need to attach properties to specific items. A line
of movement is a series of points though. Normally called a line.
--
Odd Bodkin -- maker of fine toys, tools, tables
p***@gmail.com
2017-11-03 19:03:45 UTC
Permalink
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
The have a trajectory in the sense that are created and they die and travel some path between those 2 points.
The fact that photons do not have the property of size, does not mean that their size is zero (it isn't zero, it isn't non-zero, it isn't anything). You can't say anything about the 'volume of a photon' because that property is not applicable to photons. Note that interaction between two objects does not require that either of them have the macroscopic property of volume.
And no, they do not have a trajectory. There is a place where a photon is emitted, and a place where it is absorbed, but there is no path that they travel.
RLH
2017-11-03 21:58:16 UTC
Permalink
Post by p***@gmail.com
Post by RLH
Post by p***@gmail.com
Photons do not have the property of size (volume). Nor do they have a trajectory.
They occupy some volume of space otherwise how do they interact with matter?
The have a trajectory in the sense that are created and they die and travel some path between those 2 points.
The fact that photons do not have the property of size, does not mean that their size is zero (it isn't zero, it isn't non-zero, it isn't anything). You can't say anything about the 'volume of a photon' because that property is not applicable to photons. Note that interaction between two objects does not require that either of them have the macroscopic property of volume.
And no, they do not have a trajectory. There is a place where a photon is emitted, and a place where it is absorbed, but there is no path that they travel.
Photons/wave packets do have a size and path. Otherwise the slits wouldn't need to be there and refraction gratings wouldn't work.

Tell that to a photographic plate, video CCD, cloud chamber, muon detector, radar or other radio antenna.

If photons/wave packets didn't travel in the straight lines we normally use in high energy particles, optics and radar, then none of our lenses/antenna would work in any case.

I have a little theory. If the photon you look at is represented by a sinc function with the appropriate wavelength then individual photons will 'see' the walls of the slits aand refract accordingly. Or travel through both slots simultaneously of course.

P.S. There is no functional difference between closing a box and closing your eyes. Likewise opening them. We tend to learn in the cradle that closing your eyes doesn't stop or influence things happening in the world outside. No matter how hard we try.
p***@gmail.com
2017-11-04 03:14:02 UTC
Permalink
You demonstrate that you are grossly ignorant.
Furthermore, you refuse to learn; which makes you willfully ignorant, and quite stupid.
RLH
2017-11-04 08:20:32 UTC
Permalink
Post by p***@gmail.com
You demonstrate that you are grossly ignorant.
Furthermore, you refuse to learn; which makes you willfully ignorant, and quite stupid.
So tell me oh knowledgeable one, exactly how long are the path beams in a LIGO detector and how long does it take photons to travel that length. 4.000... Kilometres and its reciprocal?

"Based on current models of astronomical events, and the predictions of the general theory of relativity, gravitational waves that originate tens of millions of light years from Earth are expected to distort the 4 kilometre mirror spacing by about 10^−18 metres, less than one-thousandth the charge diameter of a proton. Equivalently, this is a relative change in distance of approximately one part in 10^21".

Reasonably accurate. But only reasonably so. We want absolute precision. You tell me we can have it. Where is it?
David (Kronos Prime) Fuller
2017-11-03 14:37:06 UTC
Permalink
Hey RLH
Fuck Off ....You are solely an agent of Obfuscation misdirection misinformation Chaos
Eat a Shit Sandwich
RLH
2017-11-03 16:57:39 UTC
Permalink
Post by David (Kronos Prime) Fuller
Hey RLH
Fuck Off ....You are solely an agent of Obfuscation misdirection misinformation Chaos
Eat a Shit Sandwich
x ≈ n.00.....0, +-0 or .5
RLH
2017-11-04 09:31:00 UTC
Permalink
"Here are the first 50 decimal digits of pi:
3.1415926535897932384626433832795028841971693993751…
Here are the first 128 bits of pi:
11.001001000011111101101010100010001000010110100011000010001101001100010011000110011000101000101110000000110111000001110011010001...
Here are the 128 bits again, with the rounding bit for each level of precision highlighted (bits 12, 25, 54, 65, and 114):
11.001001000011111101101010100010001000010110100011000010001101001100010011000110011000101000101110000000110111000001110011010001..."

http://www.exploringbinary.com/pi-and-e-in-binary/

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